{"categories":[],"provider_name":"Hatena Blog","version":"1.0","height":"190","blog_title":"\u7a7a\u7bb1\u7cbe\u9032\u65e5\u8a18","provider_url":"https://hatena.blog","title":"AtCoder ABC 119 B - Digital Gifts (200 \u70b9)","published":"2019-02-24 23:26:39","description":"\u554f\u984c https://atcoder.jp/contests/abc119/tasks/abc119_b \u7d50\u8ad6 \u3084\u308b\u3060\u3051\u3002 \u8003\u3048\u3066\u3044\u305f\u3053\u3068 \u7cbe\u5ea6\u5927\u4e08\u592b\u304b\u306a\uff1f\u3068\u30d2\u30e4\u30d2\u30e4\u3057\u306a\u304c\u3089\u30b5\u30d6\u30df\u30c3\u30c8\u3057\u307e\u3057\u305f\u304c\u3001\u5927\u4e08\u592b\u3067\u3057\u305f\u3002 \u4eca\u601d\u3048\u3070\u914d\u5217\u3067\u6301\u3064\u5fc5\u8981\u306a\u3044\u3067\u3059\u306d\u3002 #include <bits/stdc++.h> using namespace std; int main() { ios::sync_with_stdio(false); cin.tie(0); int N; cin >> N; double x[N]; string u[N]; for (int i = 0; i < N; ++i) { cin\u2026","blog_url":"https://akeybako.hatenablog.com/","image_url":null,"html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fakeybako.hatenablog.com%2Fentry%2F2019%2F02%2F24%2F232639\" title=\"AtCoder ABC 119 B - Digital Gifts (200 \u70b9) - \u7a7a\u7bb1\u7cbe\u9032\u65e5\u8a18\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","width":"100%","url":"https://akeybako.hatenablog.com/entry/2019/02/24/232639","author_url":"https://blog.hatena.ne.jp/a_key_bako/","type":"rich","author_name":"a_key_bako"}