{"type":"rich","provider_url":"https://hatena.blog","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fancient-v.hatenadiary.org%2Fentry%2F20091112%2F1258042698\" title=\" Project Euler Problem 5 - \u601d\u3044\u3064\u3044\u305f\u3089\u66f8\u304f\u65e5\u8a18 Ex\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","provider_name":"Hatena Blog","blog_url":"https://ancient-v.hatenadiary.org/","version":"1.0","description":"\u554f\u984c5: 1 \u304b\u3089 20 \u307e\u3067\u306e\u6574\u6570\u5168\u3066\u3067\u5272\u308a\u5207\u308c\u308b\u6570\u5b57\u306e\u4e2d\u3067\u6700\u5c0f\u306e\u5024\u306f\u3044\u304f\u3089\u306b\u306a\u308b\u304b[=>\u539f\u6587\u548c\u8a33] 20\u306e\u968e\u4e57\u306f float\u578b\u3067\u6b63\u78ba\u306a\u6574\u6570\u3092\u6271\u3048\u308b\u7bc4\u56f2\u3092\u8d85\u3048\u3066\u3057\u307e\u3044\u307e\u3059\u3002\u3067\u3059\u304c\u3001\u4eca\u56de\u306f\u968e\u4e57\u3067\u306f\u306a\u304f\u6700\u5c0f\u516c\u500d\u6570\u306a\u306e\u3067 float\u3084\u3001\u3082\u3057\u304b\u3057\u305f\u3089 integer \u306e\u7bc4\u56f2\u3067\u53ce\u307e\u308b\u304b\u3082\u3057\u308c\u307e\u305b\u3093\u3002\u30c0\u30e1\u3082\u3068\u3067\u3084\u3063\u3066\u307f\u307e\u3057\u3087\u3046\u3002 \u3068\u308a\u3042\u3048\u305a\u3084\u3063\u3066\u307f\u308b (defun problem005 (N) \"1\u301cN\u306e\u6574\u6570\u306e\u6700\u5c0f\u516c\u500d\u6570\u3092\u6c42\u3081\u308b\" (let ((n 0) (lis nil)) (dotimes (n N) (setq lis (cons (1+ n) lis))) (apply #'lcm lis)))\u2026","width":"100%","height":"190","author_url":"https://blog.hatena.ne.jp/ancient-v/","title":" Project Euler Problem 5","author_name":"ancient-v","image_url":null,"published":"2009-11-12 01:18:18","url":"https://ancient-v.hatenadiary.org/entry/20091112/1258042698","categories":["Project Euler","Emacs Lisp"],"blog_title":"\u601d\u3044\u3064\u3044\u305f\u3089\u66f8\u304f\u65e5\u8a18 Ex"}