{"height":"190","provider_name":"Hatena Blog","author_name":"hamayanhamayan","title":"Triangular Relationship [AtCoder Regular Contest 102 C]","author_url":"https://blog.hatena.ne.jp/hamayanhamayan/","categories":["\u7af6\u6280\u30d7\u30ed\u30b0\u30e9\u30df\u30f3\u30b0"],"width":"100%","published":"2018-09-02 22:59:28","provider_url":"https://hatena.blog","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fblog.hamayanhamayan.com%2Fentry%2F2018%2F09%2F02%2F225928\" title=\"Triangular Relationship [AtCoder Regular Contest 102 C] - \u306f\u307e\u3084\u3093\u306f\u307e\u3084\u3093\u306f\u307e\u3084\u3093\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","image_url":null,"type":"rich","description":"https://beta.atcoder.jp/contests/arc102/tasks/arc102_a \u89e3\u6cd5 https://beta.atcoder.jp/contests/arc102/submissions/3127393(a+b) % K = 0 (a+c) % K = 0 \u3053\u308c\u3092\u8a00\u3044\u63db\u3048\u308b\u3068 (a+b) % K = (a+c) % K b % K = c % K \u3068\u306a\u308b\u3002 \u4ed6\u306e\u7d44\u5408\u305b\u3067\u3082\u3084\u308b\u3068\u3001a%K = b%K = c%K\u304c\u6210\u308a\u7acb\u3064\u3068\u308f\u304b\u308b\u3002 \u305d\u308c\u306b\u52a0\u3048\u3066 (a+b)%K=0\u306b\u306a\u308b\u305f\u3081\u306b\u306f\u3001a%K=b%K=c%K=0\u304ba%K=b%K=c%K=K/2\u306e\u3069\u3061\u3089\u304b\u3067\u3042\u308b\u3002 \u307e\u305a\u3001a\u2026","url":"https://blog.hamayanhamayan.com/entry/2018/09/02/225928","blog_url":"https://blog.hamayanhamayan.com/","blog_title":"\u306f\u307e\u3084\u3093\u306f\u307e\u3084\u3093\u306f\u307e\u3084\u3093","version":"1.0"}