{"author_name":"henteko07","type":"rich","title":"SRM536 Div2","blog_title":"\u3078\u3093\u3066\u3053\u306e\u30d6\u30ed\u30b0","blog_url":"https://blog.henteko07.com/","provider_name":"Hatena Blog","author_url":"https://blog.hatena.ne.jp/henteko07/","version":"1.0","provider_url":"https://hatena.blog","height":"190","url":"https://blog.henteko07.com/entry/20120307/1331131633","description":"\u30ec\u30fc\u30c6\u30a3\u30f3\u30b0\u304c-102\u3055\u308c\u305f\u3002 \u3051\u3069\u6c17\u306b\u3057\u306a\u3044\u3082\u3093\u2026\u2026250 (int h = tmp % 2;\u5fd8\u308c\u306650\u5206\u304f\u3089\u3044\u304b\u304b\u3063\u305f) int hoge(int n,int count,int d) { if(d == 0) { return 1; } if(d-1 == count) { return n;} return n * hoge(n,count+1,d); } int countRoots(vector <int> a) { int result = 0; if(a.size() == 1) { return 0; } for(int i = 0;i < 2;i++) { int tmp \u2026","width":"100%","categories":[],"image_url":null,"published":"2012-03-07 23:47:13","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fblog.henteko07.com%2Fentry%2F20120307%2F1331131633\" title=\"SRM536 Div2 - \u3078\u3093\u3066\u3053\u306e\u30d6\u30ed\u30b0\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>"}