{"provider_url":"https://hatena.blog","author_url":"https://blog.hatena.ne.jp/muchance/","blog_url":"https://blog.muchance.jp/","description":"\u554f\u984c Problem 20\uff1aFactorial digit sum n! means n \u00d7 (n \u2212 1) \u00d7 ... \u00d7 3 \u00d7 2 \u00d7 1For example, 10! = 10 \u00d7 9 \u00d7 ... \u00d7 3 \u00d7 2 \u00d7 1 = 3628800, and the sum of the digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27.Find the sum of the digits in the number 100! \u89e3\u7b54\u4f8b import math strNum = str(math.factorial(100))\u2026","author_name":"muchance","image_url":null,"title":"Project Euler 20","provider_name":"Hatena Blog","published":"2017-06-01 23:30:00","type":"rich","categories":["Project Euler"],"html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fblog.muchance.jp%2Fentry%2F2017%2F06%2F01%2F233000\" title=\"Project Euler 20 - mu chance or much chance ?\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","height":"190","blog_title":"mu chance or much chance ?","url":"https://blog.muchance.jp/entry/2017/06/01/233000","width":"100%","version":"1.0"}