{"author_name":"ngtkana","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fblog.ngtkana.com%2Fentry%2F2024%2F03%2F31%2F045413\" title=\"\u5fd8\u308c\u304c\u3061\u306a\u516c\u5f0f - \u30d6\u30ed\u30b0\u540d\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","published":"2024-03-31 04:54:13","url":"https://blog.ngtkana.com/entry/2024/03/31/045413","blog_title":"\u30d6\u30ed\u30b0\u540d","title":"\u5fd8\u308c\u304c\u3061\u306a\u516c\u5f0f","blog_url":"https://blog.ngtkana.com/","image_url":null,"provider_name":"Hatena Blog","width":"100%","type":"rich","categories":[],"author_url":"https://blog.hatena.ne.jp/ngtkana/","provider_url":"https://hatena.blog","description":"\u8ca0\u306e\u4e8c\u9805\u5b9a\u7406\u307f\u305f\u3044\u306a\u3084\u3064 $$ \\frac 1 { (1 - x ) ^ { 1 + n } } = \\sum _ { i \\ge 0 } \\binom { n + i } i x ^ i $$ \u91cd\u8907\u7d44\u307f\u5408\u308f\u305b $$ \\left \\lbrace x \\in \\mathbb{N}^k \\ \\middle \\vert \\ x _ 1 + \\dots + x _ k = n \\right \\rbrace = \\binom { n + k - 1 } { k - 1} $$","version":"1.0","height":"190"}