{"published":"2008-04-07 00:37:30","version":"1.0","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fboxnos.hatenablog.com%2Fentry%2F20080407%2F1207496250\" title=\" Problem 36 - 10\u9032\u6570\u3067\u30822\u9032\u6570\u3067\u3082\u56de\u6587\u6570 - \u30dc\u30af\u30ce\u30b9\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","width":"100%","type":"rich","blog_url":"https://boxnos.hatenablog.com/","description":"\u307e\u305f\u7ffb\u8a33\u3057\u3066\u307f\u308b\u3002Problem 36 - Project Euler The decimal number, 585 = 1001001001_2 (binary), is palindromic in both bases.Find the sum of all numbers, less than one million, which are palindromic in base 10 and base 2.(Please note that the palindromic number, in either base, may not include leading zeros.) \u2026","provider_url":"https://hatena.blog","provider_name":"Hatena Blog","height":"190","blog_title":"\u30dc\u30af\u30ce\u30b9","author_name":"tanakaBox","url":"https://boxnos.hatenablog.com/entry/20080407/1207496250","image_url":null,"title":" Problem 36 - 10\u9032\u6570\u3067\u30822\u9032\u6570\u3067\u3082\u56de\u6587\u6570","categories":["Scheme"],"author_url":"https://blog.hatena.ne.jp/tanakaBox/"}