{"categories":["Scheme"],"height":"190","url":"https://boxnos.hatenablog.com/entry/20080417/1208385357","blog_title":"\u30dc\u30af\u30ce\u30b9","provider_url":"https://hatena.blog","width":"100%","author_name":"tanakaBox","author_url":"https://blog.hatena.ne.jp/tanakaBox/","provider_name":"Hatena Blog","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fboxnos.hatenablog.com%2Fentry%2F20080417%2F1208385357\" title=\" \u6570\u5b66\u30ac\u30fc\u30eb\u3092\u8aad\u3080\u305e\u3049 6 - \u30d5\u30a3\u30dc\u30ca\u30c3\u30c1\u6570\u5217\u306e\u4e00\u822c\u9805 - \u30dc\u30af\u30ce\u30b9\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","title":" \u6570\u5b66\u30ac\u30fc\u30eb\u3092\u8aad\u3080\u305e\u3049 6 - \u30d5\u30a3\u30dc\u30ca\u30c3\u30c1\u6570\u5217\u306e\u4e00\u822c\u9805","description":"\u524d\u56de,\u30d5\u30a3\u30dc\u30ca\u30c3\u30c1\u6570\u5217\u306e\u6bcd\u95a2\u6570\u306e\u4e00\u822c\u9805\u3092\u6c42\u3081\u308b\u3053\u3068\u304c\u51fa\u6765\u305f\u306e\u3067\u3001\u5f8c\u306f\u3001\u30d5\u30a3\u30dc\u30ca\u30c3\u30c1\u6570\u5217\u306e\u4e00\u822c\u9805\u306b\u5411\u3051\u3066\u30b4\u30cb\u30e7\u30b4\u30cb\u30e7\u3084\u308b\u3060\u3051\u3063\u3059\u3002 \u5199\u7d4c\u4e2d\u30fb\u30fb\u30fb \u51fa\u6765\u305f\uff01\uff01\u30d5\u30a3\u30dc\u30ca\u30c3\u30c1\u6570\u5217\u306e\u4e00\u822c\u9805\u3092\u624b\u306b\u5165\u308c\u305f\uff01\uff01 \u304c\u30fb\u30fb\u30fbScheme\u3067\u3084\u308b\u3068\u8aa4\u5dee\u304c\u51fa\u3066\u3057\u307e\u3046\u3002\u56db\u6368\u4e94\u5165\u3057\u3066\u6574\u6570\u306b\u3002\u3068\u3044\u3046\u65b9\u6cd5\u3082\u3042\u308b\u3051\u3069\u3001 \u300c\u8aa4\u5dee\u7121\u3057\u3067\u89e3\u304f\u65b9\u6cd5\u304c\u3042\u308b\u300d \u305d\u3046\u3002\u6570\u5f0f\u51e6\u7406\uff01\uff01 \u3068\u3044\u3046\u3053\u3068\u3067\u3001\u4eca\u56de\u306fCommon Lisp\u3067\u66f8\u304b\u308c\u305f\u6570\u5f0f\u51e6\u7406\u30bd\u30d5\u30c8Maxima\u4f7f\u3044\u307e\u3059\u3002\u30cf\u30a4\u3002 % maxima (%i19) F(n):=(1 / sqrt(5)) * ((((1 + sqrt(5))/2)^n) - (((1 - sqrt(5))/2)^n)\u2026","type":"rich","version":"1.0","published":"2008-04-17 07:35:57","image_url":null,"blog_url":"https://boxnos.hatenablog.com/"}