{"description":"\u540c\u3058\u3088\u3046\u306a\u554f\u984c\u304c\u3042\u3063\u305f\u6c17\u304c\u3059\u308b\u3002Problem 45 - Project Euler Triangle, pentagonal, and hexagonal numbers are generated by the following formulae: Triangle Tn=n(n+1)/2 1, 3, 6, 10, 15, ... Pentagonal Pn=n(3n\u22121)/2 1, 5, 12, 22, 35, ... Hexagonal Hn=n(2n\u22121) 1, 6, 15, 28, 45, ...It can be verified that T285 = P165 = H143\u2026","blog_title":"\u30dc\u30af\u30ce\u30b9","height":"190","provider_url":"https://hatena.blog","width":"100%","provider_name":"Hatena Blog","version":"1.0","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fboxnos.hatenablog.com%2Fentry%2F20080427%2F1209268365\" title=\" Problem 45 - \u4e09\u89d2\u6570\u3001\u4e94\u89d2\u6570\u3001\u516d\u89d2\u6570 - \u30dc\u30af\u30ce\u30b9\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","type":"rich","image_url":null,"url":"https://boxnos.hatenablog.com/entry/20080427/1209268365","author_name":"tanakaBox","blog_url":"https://boxnos.hatenablog.com/","author_url":"https://blog.hatena.ne.jp/tanakaBox/","published":"2008-04-27 12:52:45","title":" Problem 45 - \u4e09\u89d2\u6570\u3001\u4e94\u89d2\u6570\u3001\u516d\u89d2\u6570","categories":["Scheme"]}