{"blog_title":"C++\u7af6\u30d7\u30ed\u5b66\u7fd2\u65e5\u8a18(\u4eee)","provider_url":"https://hatena.blog","author_name":"chiwawa_star","image_url":null,"version":"1.0","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fchiwawa-star.hatenablog.com%2Fentry%2F2016%2F05%2F09%2F023538\" title=\"ABC037-A \u9945\u982d\uff5cAtCoder - C++\u7af6\u30d7\u30ed\u5b66\u7fd2\u65e5\u8a18(\u4eee)\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","published":"2016-05-09 02:35:38","provider_name":"Hatena Blog","url":"https://chiwawa-star.hatenablog.com/entry/2016/05/09/023538","author_url":"https://blog.hatena.ne.jp/chiwawa_star/","description":"A: \u9945\u982d - AtCoder Beginner Contest 037 | AtCoder \u3092\u89e3\u304d\u307e\u3057\u305f\uff01 #include <bits/stdc++.h> using namespace std; int main(){ cin.tie( 0 ); ios::sync_with_stdio( false ); int a,b,c; cin >> a >> b >> c; int res1 = c/a; int res2 = c/b; cout << max(res1,res2) << endl; return 0; } \u2191\u63d0\u51fa\u30b3\u30fc\u30c9 A\u554f\u984c\u3060\u3057...\u6d41\u77f3\u306b\u9593\u9055\u3044\uff1f\u3068\u4e91\u3046\u304b\u3001\u4fee\u6b63\u7b87\u6240\u306a\u3044\u7b48.\u2026","type":"rich","width":"100%","categories":["AtCoder","\u30b3\u30fc\u30c9","\u7af6\u30d7\u30ed","\u7af6\u30d7\u30ed\u30e1\u30e2"],"title":"ABC037-A \u9945\u982d\uff5cAtCoder","height":"190","blog_url":"https://chiwawa-star.hatenablog.com/"}