{"width":"100%","description":"\u300e\u30d7\u30ed\u30b0\u30e9\u30df\u30f3\u30b0Haskell\u300f\u306e\u6b21\u306b\u300eReal World Haskell\u300f\u3092\u8aad\u307f\u306f\u3058\u3081\u305f\u3002 \u3067\u3082\u5148\u306b Control.Arrow \u3068\u304b Control.Applicative \u304c\u4f55\u3067\u3042\u308b\u304b\u3092\u77e5\u308a\u305f\u3044\u3002 \u3042\u308a\u304c\u305f\u3044\u3053\u3068\u306b\u65e5\u672c\u8a9e\u306e\u30d6\u30ed\u30b0\u304c\u7d50\u69cb\u3042\u308b\u306e\u3067\u8aad\u307e\u305b\u3066\u3082\u3089\u3063\u3066\u5c11\u3057\u5206\u304b\u3063\u3066\u304d\u305f\u3002 99 questions/Solutions/10 - HaskellWiki encode :: Eq a => [a] -> [(Int, a)] encode = map (\\x -> (length x, head x)) . group encode :: Eq a => [a] -> [(Int, a\u2026","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fdeve68.hatenadiary.org%2Fentry%2F20110514%2F1305391952\" title=\" Control.Arrow - \u30b3\u30fc\u30c9\u306e\u6075\u307f\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","blog_url":"https://deve68.hatenadiary.org/","height":"190","categories":[".hs"],"title":" Control.Arrow","author_url":"https://blog.hatena.ne.jp/deve68/","image_url":null,"provider_name":"Hatena Blog","blog_title":"\u30b3\u30fc\u30c9\u306e\u6075\u307f","type":"rich","published":"2011-05-14 01:52:32","url":"https://deve68.hatenadiary.org/entry/20110514/1305391952","provider_url":"https://hatena.blog","version":"1.0","author_name":"deve68"}