{"html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Ffortran66.hatenablog.com%2Fentry%2F20121227%2F1356630921\" title=\"problem 009 - fortran66\u306e\u30d6\u30ed\u30b0\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","image_url":null,"description":"\u30c6\u30ad\u30c8\u30fc\uff57 \u30bd\u30fc\u30b9\u30fb\u30d7\u30ed\u30b0\u30e9\u30e0 program PEuler009 implicit none integer :: ia, ib, ic ! a^2 + b^2 = c^2 do ic = 1, 1000 do ib = 1, ic - 1 if (ib > ic) exit ia = 1000 - ib - ic if (ia > ib) cycle if (ia <= 0) exit if (ia * ia + ib * ib == ic * ic) print *, ia, ib, ic, ':', ia * ib * ic end do end do stop end program\u2026","width":"100%","provider_name":"Hatena Blog","author_name":"fortran66","blog_title":"fortran66\u306e\u30d6\u30ed\u30b0","type":"rich","categories":["ProjectEuler"],"title":"problem 009","author_url":"https://blog.hatena.ne.jp/fortran66/","url":"https://fortran66.hatenablog.com/entry/20121227/1356630921","published":"2012-12-27 02:55:21","provider_url":"https://hatena.blog","height":"190","version":"1.0","blog_url":"https://fortran66.hatenablog.com/"}