{"author_url":"https://blog.hatena.ne.jp/fortran66/","published":"2012-12-30 00:34:34","type":"rich","title":"Problem 16","description":"2^1000\u3092\u6c42\u3081\u308b\u306e\u306b\u624b\u629c\u304d\u3057\u3066\u591a\u500d\u9577\u6574\u6570\u30e9\u30a4\u30d6\u30e9\u30ea FMLIB \u3092\u5229\u7528\u3055\u305b\u3066\u3044\u305f\u3060\u304d\u307e\u3057\u305f\u30022^1000\u301c10^300\u306a\u306e\u3067300\u6841\u5f37\u306e\u6587\u5b57\u5217\u3092\u7528\u610f\u3057\u307e\u3057\u305f\u3002 \u30bd\u30fc\u30b9\u30fb\u30d7\u30ed\u30b0\u30e9\u30e0 program PEuler016 use fmzm implicit none character(len = 350) :: str integer :: k(350) type(im) :: m m = to_im(2)**1000 call im_form('i350', m, str) read(str, '(350i1.1)') k print *, sum(k) stop end program P\u2026","provider_url":"https://hatena.blog","author_name":"fortran66","blog_title":"fortran66\u306e\u30d6\u30ed\u30b0","version":"1.0","url":"https://fortran66.hatenablog.com/entry/20121230/1356881674","categories":["ProjectEuler"],"image_url":null,"height":"190","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Ffortran66.hatenablog.com%2Fentry%2F20121230%2F1356881674\" title=\"Problem 16 - fortran66\u306e\u30d6\u30ed\u30b0\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","blog_url":"https://fortran66.hatenablog.com/","width":"100%","provider_name":"Hatena Blog"}