{"author_name":"hiroki_f","blog_title":"hiroki_f\u2019s diary","description":"\u3064\u3044\u306b\u570f\u8ad6\u30d6\u30fc\u30e0\u304c\u3084\u3063\u3066\u304d\u307e\u3057\u305f\u306d\u3002epi\u304c\u74b0\u6e96\u540c\u578b\u3060\u3068\u5168\u5c04\u306b\u306a\u308b\u3068\u306f\u9650\u3089\u306a\u3044\u306e\u306f\u306a\u3093\u3067\u304b\u3068\u805e\u304b\u308c\u305f\u306e\u3067\u8003\u3048\u3066\u307f\u307e\u3057\u305f\u3002\u53c2\u8003\u570f\u8ad6\uff1a\u30e2\u30ce\u304b\u3064\u30a8\u30d4\u306a\u5c04 \u518d\u3073 - \u6a9c\u5c71\u6b63\u5e78\u306e\u30ad\u30de\u30a4\u30e9\u98fc\u80b2\u8a18 abstract algebra - Showing two ring homomorphisms that agree on the integers must agree on the rationals - Mathematics Stack Exchange\u74b0\u6e96\u540c\u578b\u3068\u306f 1 f(a + b) = f(a) + f(b) 2 f(ab) = f(a)f(b) 3 f(1) = 1. \u304c\u6210\u308a\u7acb\u3064\u95a2\u6570\u306e\u3053\u3068\u3092\u8a00\u2026","provider_url":"https://hatena.blog","width":"100%","height":"190","version":"1.0","url":"https://hirokif.hatenablog.com/entry/20160410/1460265446","published":"2016-04-10 14:17:26","author_url":"https://blog.hatena.ne.jp/hiroki_f/","blog_url":"https://hirokif.hatenablog.com/","provider_name":"Hatena Blog","image_url":null,"categories":[],"title":"epi\u304c\u5168\u5c04\u306b\u306a\u3089\u306a\u3044\u4f8b","type":"rich","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fhirokif.hatenablog.com%2Fentry%2F20160410%2F1460265446\" title=\"epi\u304c\u5168\u5c04\u306b\u306a\u3089\u306a\u3044\u4f8b - hiroki_f\u2019s diary\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>"}