{"provider_name":"Hatena Blog","title":"\u4e09\u89d2\u5f62\u306e\u6570\uff084\uff09","type":"rich","categories":["\u6570\u5b66"],"version":"1.0","author_url":"https://blog.hatena.ne.jp/inamori/","provider_url":"https://hatena.blog","url":"https://inamori.hateblo.jp/entry/20070618/p1","width":"100%","author_name":"inamori","height":"190","image_url":null,"blog_title":"inamori\u2019s diary","blog_url":"https://inamori.hateblo.jp/","published":"2007-06-18 00:00:00","description":"\u5408\u540c\u306a\u4e09\u89d2\u5f62\u306e\u6570\u3082\u6570\u3048\u3066\u304a\u3053\u3046\u3002 T = S1 + S2 + S3 = (S + S3) / 2 n\u304c3\u3067\u5272\u308a\u5207\u308c\u308b\u3068\u304d\u3001 T = (n2-3n+6)/2 + [(n-1)/2]/2 n\u304c\u5076\u6570\u306e\u3068\u304d\u3001 T = (n2-3n+6)/2 + (n-1)/4 = (n2+3)/12 n\u304c\u5947\u6570\u306e\u3068\u304d\u3001 T = (n2-3n+6)/2 + (n-2)/4 = n2/12 n\u304c3\u3067\u5272\u308a\u5207\u308c\u306a\u3044\u3068\u304d\u3001 T = (n2-3n+2)/2 + [(n-1)/2]/2 n\u304c\u5076\u6570\u306e\u3068\u304d\u3001 T = (n2-3n+2)/2 + (n-1)/4 = (n2-1)/12 n\u304c\u5947\u6570\u306e\u3068\u304d\u3001 T = (n2-3n+2)/2 + \u2026","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Finamori.hateblo.jp%2Fentry%2F20070618%2Fp1\" title=\"\u4e09\u89d2\u5f62\u306e\u6570\uff084\uff09 - inamori\u2019s diary\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>"}