{"width":"100%","height":"190","url":"https://inamori.hateblo.jp/entry/20090516/p1","blog_url":"https://inamori.hateblo.jp/","provider_url":"https://hatena.blog","type":"rich","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Finamori.hateblo.jp%2Fentry%2F20090516%2Fp1\" title=\"Project Euler 131 - inamori\u2019s diary\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","blog_title":"inamori\u2019s diary","published":"2009-05-16 00:00:00","image_url":null,"categories":["\u6570\u5b66","C++"],"provider_name":"Hatena Blog","description":"\u30d7\u30ed\u30b8\u30a7\u30af\u30c8\u30aa\u30a4\u30e9\u30fc http://projecteuler.net/index.php Q131. n3 + pn2\u304c\u7acb\u65b9\u6570\u3068\u306a\u308a\u3046\u308b\u7d20\u6570p\u306e100\u4e07\u4ee5\u4e0b\u306e\u500b\u6570 n3 + pn2 = (n + k)3 (p-3k)n2 - 3k2n - k3 = 0 D = 4pk - 3k2 \u5224\u5225\u5f0f\u304c\u5e73\u65b9\u6570\u3060\u304b\u3089\u3001 4pk - 3k2 = m2 3m2 + (3k-2p)2 = 4p2 \u3053\u3053\u3067\u632b\u6298\u3057\u305f\u3002Python\u3067\u66f8\u3044\u3066\u8a71\u306b\u306a\u3089\u306a\u304b\u3063\u305f\u306e\u3067\u3001C++\u3067\u66f8\u3044\u305f\u300232\u30d3\u30c3\u30c8\u306e\u7bc4\u56f2\u3067\u8a08\u7b97\u3067\u304d\u306a\u3044\u306e\u3067\u3001double\u3092\u4f7f\u3063\u3066\u9069\u5f53\u306b\u3054\u307e\u304b\u3057\u305f\u3002","author_name":"inamori","version":"1.0","author_url":"https://blog.hatena.ne.jp/inamori/","title":"Project Euler 131"}