{"title":"Project Euler 108","categories":["PE","\u6570\u5b66","\u30d7\u30ed\u30b0\u30e9\u30df\u30f3\u30b0"],"image_url":null,"author_name":"inamori","blog_title":"inamori\u2019s diary","blog_url":"https://inamori.hateblo.jp/","url":"https://inamori.hateblo.jp/entry/20100624/p1","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Finamori.hateblo.jp%2Fentry%2F20100624%2Fp1\" title=\"Project Euler 108 - inamori\u2019s diary\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","width":"100%","author_url":"https://blog.hatena.ne.jp/inamori/","height":"190","version":"1.0","description":"http://projecteuler.net/index.php?section=problems&id=108 (x - n)(y - n) = n2 \u3060\u304b\u3089\u3001n\u3092\u7d20\u56e0\u6570\u5206\u89e3\u3057\u3066\u3001 n = p1e1\u2026pmem \u3068\u3059\u308b\u3068\u3001\u89e3\u306e\u500b\u6570\u306f\u3001 ((2e1 + 1)\u2026(2em + 1) + 1) / 2 \u3068\u306a\u308a\u307e\u3059\u3002 \u5358\u306b\u5272\u3063\u3066\u3044\u3063\u3066\u7d20\u56e0\u6570\u5206\u89e3\u3059\u308b\u306e\u306f\u9045\u3044\u306e\u3067\u3001\u30a8\u30e9\u30c8\u30b9\u30c6\u30cd\u30b9\u306e\u3075\u308b\u3044\u7684\u306b\u7d20\u56e0\u6570\u5206\u89e3\u3092\u3057\u307e\u3059\u3002\u3069\u3053\u307e\u3067\u7d20\u56e0\u6570\u5206\u89e3\u3059\u308c\u3070\u3044\u3044\u306e\u304b\u308f\u304b\u3089\u306a\u3044\u306e\u3067\u3001\u5c11\u3057\u305a\u3064\u307e\u3068\u3081\u3066\u8a08\u7b97\u3057\u307e\u3059\u3002\u30d9\u30f3\u30c1\u30de\u30fc\u30af\u3057\u3066\u307f\u308b\u3068\u3001500\u305a\u3064\u304c\u6700\u3082\u901f\u3044\u3068\u3044\u3046\u7d50\u679c\u306b\u306a\u308a\u307e\u3057\u305f\u3002 \u672c\u5f53\u306f\u7d20\u56e0\u6570\u5206\u89e3\u3092\u3059\u308b\u5fc5\u8981\u3082\u7121\u3044\u306e\u3067\u3059\u304c\u3001\u305d\u308c\u306f\u6b21\u3067\u2026","provider_url":"https://hatena.blog","published":"2010-06-24 00:00:00","type":"rich","provider_name":"Hatena Blog"}