{"html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Finamori.hateblo.jp%2Fentry%2F20111218%2Fp1\" title=\"Scala\u3067Project Euler\uff08116\uff09 - inamori\u2019s diary\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","height":"190","image_url":null,"categories":["Scala"],"provider_name":"Hatena Blog","title":"Scala\u3067Project Euler\uff08116\uff09","width":"100%","blog_url":"https://inamori.hateblo.jp/","url":"https://inamori.hateblo.jp/entry/20111218/p1","author_url":"https://blog.hatena.ne.jp/inamori/","author_name":"inamori","type":"rich","provider_url":"https://hatena.blog","published":"2011-12-18 00:00:00","version":"1.0","blog_title":"inamori\u2019s diary","description":"Problem 78\u5206\u5272\u6570p(k)\u306b\u306f\u3001\u5b9f\u306f\u6b21\u306e\u3088\u3046\u306a\u6f38\u5316\u5f0f\u304c\u3042\u308a\u307e\u3059\u3002 p(k) = p(k - 1) + p(k - 2) - p(k - 5) - p(k - 7) + p(k - 12) + p(k - 15) - \u2026 p(0) = 1 p(k) = 0 (k \u6f38\u5316\u5f0f\u306ep\u306e\u4e2d\u306ek - m\u306em\u306f\u4e94\u89d2\u6570\u306b\u306a\u3063\u3066\u3044\u307e\u3059\u3002\u7b26\u53f7\u306f\u3001+ + - - + + - -\u3068\u306a\u308a\u307e\u3059\u3002 \u3053\u308c\u3067\u5927\u304d\u306a\u6570\u306e\u5206\u5272\u6570\u306b\u3064\u3044\u3066\u3082\u6c42\u3081\u308b\u3053\u3068\u304c\u3067\u304d\u307e\u3059\u3002"}