{"width":"100%","type":"rich","title":" \u6761\u4ef6\u7bc4\u56f2\u5f0f\u306e\u4f7f\u3044\u65b9","url":"https://mametter.hatenablog.com/entry/20071126/p1","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fmametter.hatenablog.com%2Fentry%2F20071126%2Fp1\" title=\" \u6761\u4ef6\u7bc4\u56f2\u5f0f\u306e\u4f7f\u3044\u65b9 - \u307e\u3081\u3081\u3082\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","blog_url":"https://mametter.hatenablog.com/","author_name":"ku-ma-me","description":"\u5927\u304d\u3081\u306e\u30b3\u30f3\u30bd\u30fc\u30eb\u3067\u5b9f\u884c\u3057\u3066\u304f\u3060\u3055\u3044\u3002 W, H = 44, 54 c = 7 + 42 * W a = [0] * W * H g = d = 0 f = proc do |n| a[c] += 1 o = a.map {|z| \" :#\"[z, 1] * 2 }.join.scan(/.{#{W * 2}}/) puts \"\\f\" + o.map {|l| l.rstrip }.join(\"\\n\") sleep 0.005 d += 1 - 2 * ((g ^= 1 << n) >> n) c += [1, W, -1, -W][d %= 4] end 1024.times do !!(!\u2026","height":"190","version":"1.0","provider_name":"Hatena Blog","published":"2007-11-26 00:00:00","image_url":null,"blog_title":"\u307e\u3081\u3081\u3082","author_url":"https://blog.hatena.ne.jp/ku-ma-me/","categories":["Ruby"],"provider_url":"https://hatena.blog"}