{"description":"\\(\\displaystyle \\lim_{n \\to \\infty} a_n\\)\u306e\u6975\u9650\u5024\u3092\u6c42\u3081\u3088\uff0e\u3053\u3053\u3067\uff0c\\(\\displaystyle a_n = 2 + \\frac{2}{a_{n-1}}\\)\uff0c\\(a_0 = 2\\)\u3068\u3059\u308b\uff0e \u2605\u9806\u5e8f\u7acb\u3066\u305f\u6f14\u7e79\u304c\u5fc5\u8981\u2605","blog_title":"\uff11\uff10\u5e74\u3076\u308a\u306e\u6570\u5b66\u5c11\u5e74\u306e\u90e8\u5c4b","height":"190","categories":["\u5927\u5b66\u7de8\u5165\u8a66\u9a13"],"provider_name":"Hatena Blog","width":"100%","type":"rich","blog_url":"https://mathematic.hatenablog.com/","author_url":"https://blog.hatena.ne.jp/entar77/","image_url":null,"author_name":"entar77","title":"\u3010\u5927\u5b66\u7de8\u5165\u8a66\u9a13071\u3011\u5343\u8449\u5927\u5b66","provider_url":"https://hatena.blog","url":"https://mathematic.hatenablog.com/entry/2016/01/19/211038","version":"1.0","published":"2016-01-19 21:10:38","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fmathematic.hatenablog.com%2Fentry%2F2016%2F01%2F19%2F211038\" title=\"\u3010\u5927\u5b66\u7de8\u5165\u8a66\u9a13071\u3011\u5343\u8449\u5927\u5b66 - \uff11\uff10\u5e74\u3076\u308a\u306e\u6570\u5b66\u5c11\u5e74\u306e\u90e8\u5c4b\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>"}