{"url":"https://melheaven.hatenadiary.jp/entry/abc142abc","blog_url":"https://melheaven.hatenadiary.jp/","width":"100%","version":"1.0","height":"190","author_name":"electric-city","author_url":"https://blog.hatena.ne.jp/electric-city/","image_url":"https://cdn-ak.f.st-hatena.com/images/fotolife/e/electric-city/20200319/20200319193051.jpg","provider_name":"Hatena Blog","blog_title":"\u5c71\u4e0b\u8aa0\u4e8c\u90ce\u306eIT\u3068\u30d5\u30a9\u30fc\u30c8\u30ca\u30a4\u30c8\u3068\u91ce\u7403\u30d6\u30ed\u30b0","categories":["AtCoder","Python"],"description":"\u524d\u66f8\u304d AtCoder Beginner Contest 142 A\u301cC\u554f\u984c\u3092\u89e3\u304d\u307e\u3057\u305f\u3002 A\u554f\u984c \u96e3\u6613\u5ea6\uff1a\u7070 \u6642\u9593\uff1a3\u5206 atcoder.jp N=int(input()) _count=0 for i in range(1,N+1): if i%2==1: _count+=1 print(_count/N) B\u554f\u984c \u96e3\u6613\u5ea6\uff1a\u7070 \u6642\u9593\uff1a3\u5206 atcoder.jp N,K = map(int,input().split()) h = list(map(int, input().split())) print(len([i for i in h if i>=K])) C\u554f\u984c \u96e3\u6613\u5ea6\uff1a\u7070 \u6642\u9593\uff1a1\u2026","type":"rich","provider_url":"https://hatena.blog","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fmelheaven.hatenadiary.jp%2Fentry%2Fabc142abc\" title=\"AtCoder Beginner Contest 142 A\u301cC\u554f\u984c - \u5c71\u4e0b\u8aa0\u4e8c\u90ce\u306eIT\u3068\u30d5\u30a9\u30fc\u30c8\u30ca\u30a4\u30c8\u3068\u91ce\u7403\u30d6\u30ed\u30b0\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","title":"AtCoder Beginner Contest 142 A\u301cC\u554f\u984c","published":"2021-03-18 15:52:39"}