{"version":"1.0","type":"rich","image_url":"https://cdn-ak.f.st-hatena.com/images/fotolife/e/electric-city/20200319/20200319193051.jpg","provider_url":"https://hatena.blog","height":"190","provider_name":"Hatena Blog","blog_title":"\u5c71\u4e0b\u8aa0\u4e8c\u90ce\u306eIT\u3068\u30d5\u30a9\u30fc\u30c8\u30ca\u30a4\u30c8\u3068\u91ce\u7403\u30d6\u30ed\u30b0","width":"100%","title":"AtCoder Beginner Contest 155 \u904e\u53bb\u554f(A~C)","categories":["Python","AtCoder"],"url":"https://melheaven.hatenadiary.jp/entry/atcoder155","blog_url":"https://melheaven.hatenadiary.jp/","published":"2020-04-20 18:33:04","author_name":"electric-city","author_url":"https://blog.hatena.ne.jp/electric-city/","description":"A\u554f\u984c \u7279\u306b\u554f\u984c\u306a\u3057 a = list(map(int, input().split())) if len(set(a))==2: print('Yes') else: print('No') B\u554f\u984c \u7279\u306b\u554f\u984c\u306a\u304f n = int(input()) aa = list(map(int, input().split())) for a in aa: if a%2==0 and (a%3!=0 and a%5!=0): print('DENIED') exit(0) print('APPROVED') C\u554f\u984c collections.Counter()\u3092\u7528\u3044\u308b\u3053\u3068\u3067\u3001 \u8981\u7d20\u306e\u51fa\u73fe\u56de\u6570\u3092\u30c7\u30a3\u30ec\u30af\u30c8\u30ea\u2026","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fmelheaven.hatenadiary.jp%2Fentry%2Fatcoder155\" title=\"AtCoder Beginner Contest 155 \u904e\u53bb\u554f(A~C) - \u5c71\u4e0b\u8aa0\u4e8c\u90ce\u306eIT\u3068\u30d5\u30a9\u30fc\u30c8\u30ca\u30a4\u30c8\u3068\u91ce\u7403\u30d6\u30ed\u30b0\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>"}