{"html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fp-beginner.hatenadiary.org%2Fentry%2F20110220%2F1298214674\" title=\"2011-02-20\uff08\u305d\u306e\uff12\uff09 - \u65e5\u8a18\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","version":"1.0","categories":[],"provider_name":"Hatena Blog","published":"2011-02-20 00:11:14","description":"\u30fb\u5168\u7136\u5206\u304b\u3089\u306a\u3044\u306e\u3060\u304c\u3002\u3002\u5206\u6bcd\u3068\u5206\u5b50\u304c\u9055\u3046\u591a\u6b21\u5143\u914d\u5217\u306e\u7a4d\uff1f\uff1f /* \u884c\u5217x, y\u306e\u7a4d\u3092\u8868\u793a\u3059\u308b\u30d7\u30ed\u30b0\u30e9\u30e0\u3092\u4f5c\u6210\u305b\u3088\u3002 #include int main(void) { int i, j, k; int ma[2][3] = { {1, 2, 3}, {4, 5, 6} }; int mb[3][2] = { {1, 5}, {5, 3}, {8, 1} }; int mc[2][2] = { 0 }; for (i = 0; i { for (k = 0; k for (j = 0; j mc[i][k] += ma[i][j] * mb[j][k]; } for (i = 0; i { f\u2026","provider_url":"https://hatena.blog","title":"2011-02-20\uff08\u305d\u306e\uff12\uff09","author_name":"p_beginner","blog_title":"\u65e5\u8a18","blog_url":"https://p-beginner.hatenadiary.org/","url":"https://p-beginner.hatenadiary.org/entry/20110220/1298214674","type":"rich","image_url":null,"author_url":"https://blog.hatena.ne.jp/p_beginner/","width":"100%","height":"190"}