{"type":"rich","title":"AOJ 0003 Is it a Right Triangle?","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fperyaudo.hatenablog.com%2Fentry%2F20100728%2F1280313266\" title=\"AOJ 0003 Is it a Right Triangle? - \u30da\u30ea\u30e3\u30a6\u30c9\u306e\u65e5\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","description":"lvalue required as left operand of assignment\u3001\u3068\u304b\u3044\u3046\u610f\u5473\u4e0d\u660e\u306a\u30a8\u30e9\u30fc\u306b\u60a9\u307e\u305b\u3089\u308c\u3066\u7d50\u5c40==\u3092=\u3068\u66f8\u3044\u3066\u305f\u3060\u3051\u306e\u30dd\u30ab\u30df\u30b9\u3060\u3063\u305f\u3068\u6c17\u4ed8\u3044\u3066\u3001\u7d50\u5c408'39\"\u3060\u3063\u305f\u3002 #include <cstdio> int main(){ int N; scanf(\"%d\", &N); for(int i = 0; i < N; i++){ int a, b, c; scanf(\"%d %d %d\\n\", &a, &b, &c); puts(((a *a + b*b == c*c) || (a*a + c*c == b*b) || (b*b + c*c == a*a\u2026","version":"1.0","provider_url":"https://hatena.blog","blog_url":"https://peryaudo.hatenablog.com/","author_name":"peryaudo","width":"100%","provider_name":"Hatena Blog","author_url":"https://blog.hatena.ne.jp/peryaudo/","image_url":null,"blog_title":"\u30da\u30ea\u30e3\u30a6\u30c9\u306e\u65e5","height":"190","categories":["Programming","Algorithm","AOJ"],"published":"2010-07-28 19:34:26","url":"https://peryaudo.hatenablog.com/entry/20100728/1280313266"}