{"image_url":null,"url":"https://propella.hatenablog.com/entry/20110222/p1","height":"190","blog_url":"https://propella.hatenablog.com/","width":"100%","provider_url":"https://hatena.blog","published":"2011-02-22 00:00:00","provider_name":"Hatena Blog","blog_title":"\u8a00\u8a9e\u30b2\u30fc\u30e0","author_url":"https://blog.hatena.ne.jp/propella/","categories":["\u8a00\u8a9e"],"author_name":"propella","version":"1.0","description":"\u30d1\u30bf\u30fc\u30f3\u30de\u30c3\u30c1\u306e\u610f\u5473\u306b\u3064\u3044\u3066\u8003\u3048\u3066\u3044\u308b\u3002\u7c21\u5358\u306a\u30d1\u30bf\u30fc\u30f3\u30de\u30c3\u30c1\u306e\u4f8b\u3068\u3057\u3066\u306f\u3001 (x, y) = (1, 2) \u306e\u3088\u3046\u306b\u66f8\u304f\u3068\u3001x \u306b 1 \u304c y \u306b 2 \u304c\u675f\u7e1b\u3055\u308c\u308b\u3068\u3044\u3046\u3082\u306e\u3002Scala \u3084 F# \u3084Haskell \u306a\u3069\u306e\u6700\u8fd1\u306e\u8a00\u8a9e\u3067\u306f\u30d1\u30bf\u30fc\u30f3\u30de\u30c3\u30c1\u3092\u4e00\u822c\u5316\u3057\u3066\u3001\u30c7\u30fc\u30bf\u69cb\u9020\u306e\u307f\u306a\u3089\u305a\u3069\u306e\u3088\u3046\u306a\u95a2\u6570\u3092\u4f7f\u3063\u3066\u3082\u30d1\u30bf\u30fc\u30f3\u30de\u30c3\u30c1\u304c\u51fa\u6765\u308b\u3002\u305f\u3068\u3048\u3070 Haskell \u3067\u306f\u3001 $ ghci Prelude> :set -XViewPatterns Prelude> let half n = n / 2 Prelude> let (half -> n) = 10 in n 5.0 \u306e\u3088\u3046\u306b\u5909\u6570 n \u306b\u675f\u7e1b\u3059\u308b\u2026","type":"rich","title":" salmacis: \u30d1\u30bf\u30fc\u30f3\u30de\u30c3\u30c1\u306e\u610f\u5473(\u5931\u6557)","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fpropella.hatenablog.com%2Fentry%2F20110222%2Fp1\" title=\" salmacis: \u30d1\u30bf\u30fc\u30f3\u30de\u30c3\u30c1\u306e\u610f\u5473(\u5931\u6557) - \u8a00\u8a9e\u30b2\u30fc\u30e0\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>"}