{"width":"100%","author_url":"https://blog.hatena.ne.jp/Pulin/","url":"https://pulin.hateblo.jp/entry/20161222/1482378256","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fpulin.hateblo.jp%2Fentry%2F20161222%2F1482378256\" title=\"\u865a\u6570\u5358\u4f4d\u306e\u865a\u6570\u5358\u4f4d\u4e57 - \u5fa1\u5149\u5802\u4e16\u754c~Pulin\u306e\u65e5\u8a18\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","title":"\u865a\u6570\u5358\u4f4d\u306e\u865a\u6570\u5358\u4f4d\u4e57","provider_name":"Hatena Blog","description":"\u865a\u6570\u5358\u4f4d\u3092\u865a\u6570\u5358\u4f4d\u4e57\u3057\u305f\u3089\u3069\u3046\u306a\u308b\u304b\u3002 i=exp(i\u03c0/2)\u3060\u304b\u3089\u3001\u3053\u308c\u3092i\u4e57\u3057\u3066 i^i=exp*1\u3001(n=0,1,2,3,...)\u306a\u306e\u3067\u4e0a\u306e\u5024\u306fn=0\u306e\u5834\u5408\u3002 *1:i\u03c0/2)i)=exp^(-\u03c0/2) \u22520.20788 \u7a0b\u306b\u306a\u308b\u3002 \u4e00\u822c\u306bi^i=exp(-(2n\u03c0+\u03c0/2","version":"1.0","height":"190","categories":["\u96d1\u611f"],"author_name":"Pulin","published":"2016-12-22 12:44:16","provider_url":"https://hatena.blog","blog_title":"\u5fa1\u5149\u5802\u4e16\u754c~Pulin\u306e\u65e5\u8a18","image_url":null,"blog_url":"https://pulin.hateblo.jp/","type":"rich"}