{"blog_url":"https://tamani.hatenadiary.jp/","title":"AtCoder Beginner Contest 088 C","author_name":"tsuzuki670","categories":["AtCoder","Ruby"],"image_url":null,"width":"100%","author_url":"https://blog.hatena.ne.jp/tsuzuki670/","height":"190","description":"atcoder.jp \u7d50\u679c \u4e00\u767aAC \u5b66\u3093\u3060\u3053\u3068 \u4e8c\u6b21\u5143\u914d\u5217\u306e\u521d\u671f\u5316\u306fmap\u3092\u3064\u304b\u3046\u3053\u3068\u3002Array.new(3, Array.new(3, 0))\u3068\u304b\u3060\u3068\u5404\u8981\u7d20\u3092\u540c\u4e00\u306e\u30aa\u30d6\u30b8\u30a7\u30af\u30c8\u3068\u307f\u306a\u3057\u3066\u3057\u307e\u3044\u5024\u304c\u9023\u52d5\u3057\u3066\u3057\u307e\u3046\u3002\uff09 \u6700\u521d\u306b\u66f8\u3044\u305f\u30b3\u30fc\u30c9 c = [] 3.times{c << gets.split().map(&:to_i)} d = Array.new(3).map{Array.new(3,0)} (0..2).each do |i| (0..2).each do |j| d[i][j] = c[i][0] + c[0][j] - c[0][0] end end puts c==d ? \u2026","type":"rich","version":"1.0","published":"2018-12-22 19:54:48","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Ftamani.hatenadiary.jp%2Fentry%2F2018%2F12%2F22%2F195448\" title=\"AtCoder Beginner Contest 088 C - tamani\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","provider_url":"https://hatena.blog","blog_title":"tamani","url":"https://tamani.hatenadiary.jp/entry/2018/12/22/195448","provider_name":"Hatena Blog"}