{"author_name":"OviskoutaR","blog_title":"\u4e09\u6d66\u30ce\u30fc\u30c8","width":"100%","provider_url":"https://hatena.blog","published":"2020-01-16 09:45:54","author_url":"https://blog.hatena.ne.jp/OviskoutaR/","url":"https://www.k-pmpstudy.com/entry/2020/01/16/AGHlimit","title":"\u76f8\u52a0\u30fb\u76f8\u4e57\u30fb\u8abf\u548c\u5e73\u5747\u306e\u6975\u9650\u5024","provider_name":"Hatena Blog","description":"$\\quad $ \u5b9f\u6570\u5217 $ \\{a _ n\\}, a _ n>0 ~ (\\forall n) $ \u306b\u5bfe\u3057\u3066\uff0c\u76f8\u52a0\u5e73\u5747 $ A _ n $ \uff0c\u76f8\u4e57\u5e73\u5747 $ G _ n $ \uff0c\u8abf\u548c\u5e73\u5747 $ H _ n $ \u306f\u6b21\u306e\u3088\u3046\u306b\u5b9a\u7fa9\u3055\u308c\u308b\uff0e \\begin{align} A _ n &= \\frac{a _ 1 + a _ 2 + \\cdots + a _ n}{n} \\\\ G _ n &= \\sqrt[n]{a _ 1 a _ 2 \\cdots a _ n} \\\\ \\frac{1}{H _ n} &= \\frac{1}{n} \\left(\\frac{1}{a _ 1} + \\frac{1}{a _ 2} \u2026","height":"190","blog_url":"https://www.k-pmpstudy.com/","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fwww.k-pmpstudy.com%2Fentry%2F2020%2F01%2F16%2FAGHlimit\" title=\"\u76f8\u52a0\u30fb\u76f8\u4e57\u30fb\u8abf\u548c\u5e73\u5747\u306e\u6975\u9650\u5024 - \u4e09\u6d66\u30ce\u30fc\u30c8\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","categories":["\u6570\u5b66","\u89e3\u6790\u5b66"],"type":"rich","image_url":null,"version":"1.0"}