{"height":"190","version":"1.0","author_url":"https://blog.hatena.ne.jp/zuruyasumineko2002/","type":"rich","title":"\u4fee\u6b63\u96e2\u6563\u30b3\u30b5\u30a4\u30f3\u9006\u5909\u63db\u3068\u306f\uff1f","published":"2022-08-03 06:49:01","blog_url":"https://zuruyasumineko2002.hatenablog.com/","blog_title":"zuruyasumineko2002\u2019s blog","description":"\u307e\u305a\u3001\u4fee\u6b63\u96e2\u6563\u30b3\u30b5\u30a4\u30f3\u5909\u63db\u306f \\begin{equation} S(r) = \\sum_{k=0}^{N/2-1}p'(k){ \\rm cos} ( \\frac{2\u03c0}{N}(k+ \\frac{1}{2})(r+ \\frac{1}{2})) \\end{equation} \u3068DCT\u2163\u3067\u8868\u305b\u305f\u3002 \u3088\u3063\u3066\u9006\u5909\u63db\u304c\u6210\u7acb\u3059\u308b\u3002 \\begin{equation} p'(k) = \\sum_{r=0}^{N/2-1}S(r){ \\rm cos}( \\frac{2\u03c0}{N}(k+ \\frac{1}{2})(r+ \\frac{1}{2})) \\end{equation} \u3053\u3053\u3067 $ p'(k) $ \u306f\u3001\u5909\u63db\u5bfe\u8c61\u2026","url":"https://zuruyasumineko2002.hatenablog.com/entry/2022/08/03/064901","width":"100%","provider_name":"Hatena Blog","categories":[],"image_url":"https://cdn-ak.f.st-hatena.com/images/fotolife/z/zuruyasumineko2002/20220803/20220803220315.png","provider_url":"https://hatena.blog","html":"<iframe src=\"https://hatenablog-parts.com/embed?url=https%3A%2F%2Fzuruyasumineko2002.hatenablog.com%2Fentry%2F2022%2F08%2F03%2F064901\" title=\"\u4fee\u6b63\u96e2\u6563\u30b3\u30b5\u30a4\u30f3\u9006\u5909\u63db\u3068\u306f\uff1f - zuruyasumineko2002\u2019s blog\" class=\"embed-card embed-blogcard\" scrolling=\"no\" frameborder=\"0\" style=\"display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;\"></iframe>","author_name":"zuruyasumineko2002"}