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  <author_name>about_hiroppy</author_name>
  <author_url>https://blog.hatena.ne.jp/about_hiroppy/</author_url>
  <blog_title>ひろっぴーのふろっぴー</blog_title>
  <blog_url>https://about-hiroppy.hatenadiary.org/</blog_url>
  <categories>
    <anon>project euler</anon>
  </categories>
  <description>11. 縦横斜め4つの数字の積の最大を出力する 実質、下、右、斜め下右、左だけでいいです。 #define smax 20 int table[smax][smax]; int main(void){ rep(i,smax) rep(j,smax) cin &gt;&gt; table[i][j]; int res=-1; rep(i,smax){ int a[4]={}; rep(j,smax){ if(j+3 &lt; smax) a[0] = table[i][j]*table[i][j+1]*table[i][j+2]*table[i][j*3]; //右 if(i+3 &lt; smax) a[1] = t…</description>
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  <provider_name>Hatena Blog</provider_name>
  <provider_url>https://hatena.blog</provider_url>
  <published>2012-06-09 03:25:46</published>
  <title>project euler 11~15</title>
  <type>rich</type>
  <url>https://about-hiroppy.hatenadiary.org/entry/20120609/1339266346</url>
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