atlas_neo46 https://blog.hatena.ne.jp/atlas_neo46/ atlas-open blog https://atlas-open2.hatenadiary.jp/ 数学 出典：関数特定する問題作ってみた！ - 工作大好きの二乗 関数f(a,b）ab≠0 a,bは実数 f(2,2)=1f(5,5)=2.5f(0.5,0.5)=0.05f(3,6)=2f(6,3)=2 （1）f(a,b) を a,bを用いて表せ ぱっと思いつくやつ f(a,b) = ab/(a+b) f(2,2)=2×2/(2+2) = 4/4 = 1 OK f(5,5)=5×5/(5+5) =25/10= 2.5 OK f(0.5,0.5)=0.5×0.5/(0.5+0.5) =0.05/1=0.05 OK f(3,6)=3×6/(3+6) =18/9=2 OK f(6,3)=2 a,bの対称性… 190 <iframe src="https://hatenablog-parts.com/embed?url=https%3A%2F%2Fatlas-open2.hatenadiary.jp%2Fentry%2F2026%2F04%2F06%2F100131" title="関数を求める（勘） - atlas-open blog" class="embed-card embed-blogcard" scrolling="no" frameborder="0" style="display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;"></iframe> Hatena Blog https://hatena.blog 2026-04-06 10:01:31 rich https://atlas-open2.hatenadiary.jp/entry/2026/04/06/100131 1.0 100%