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  <description>Fermat's little theoremを乱択アルゴリズムで表現することを考える． p : prime number a in {1, 2, ..., p-1} (mod p) p=5, a=2 (mod5) m, n; integers m&gt;n&gt;0 m = qm+r 0 &lt; r &lt; n m = 13, n = 8 13 = 18 + 5 13 5 (mod 8) &lt; Fermat's little theorem - Wikipedia</description>
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  <published>2018-04-05 11:27:42</published>
  <title>乱択アルゴリズム　１</title>
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