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  <author_name>hiratara</author_name>
  <author_url>https://blog.hatena.ne.jp/hiratara/</author_url>
  <blog_title>Pixel Pedals of Tomakomai</blog_title>
  <blog_url>https://hiratara.hatenadiary.jp/</blog_url>
  <categories>
    <anon>数学</anon>
    <anon>技術</anon>
  </categories>
  <description>概説微分積分の問題3.21の解答。x^3 + x^2 - 3 = 0 と x^4 - x - 1 = 0 を解く問題。 def f1(x): return float(x) ** 3 + float(x) ** 2 - 3 def df1(x): return 3. * float(x) ** 2 + 2. * x def f2(x): return float(x) ** 4 - float(x) - 1 def df2(x): return 4. * float(x) ** 3 - 1 def newton(f, df, a0, n): if n == 0: return a0 a = n…</description>
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  <provider_name>Hatena Blog</provider_name>
  <provider_url>https://hatena.blog</provider_url>
  <published>2012-06-06 16:14:56</published>
  <title>問題3.21の解答(ニュートン法)</title>
  <type>rich</type>
  <url>https://hiratara.hatenadiary.jp/entry/20120606/1338966896</url>
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