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  <author_name>inamori</author_name>
  <author_url>https://blog.hatena.ne.jp/inamori/</author_url>
  <blog_title>inamori’s diary</blog_title>
  <blog_url>https://inamori.hateblo.jp/</blog_url>
  <categories>
    <anon>数学</anon>
    <anon>アルゴリズム</anon>
    <anon>Python</anon>
  </categories>
  <description>エラトステネスのふるいの速度を確認します。まずは最も単純なもの。 def sieve1(N): a = [ True ] * (N + 1) for p in takewhile(lambda p: p * p &lt;= N, (n for n in count(2) if a[n])): for k in xrange(p * 2, N + 1, p): a[k] = False return [ n for n in xrange(2, N + 1) if a[n] ] t0 = time.clock() N = 10 ** 6 primes = sieve1(N) print len(pri…</description>
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  <image_url></image_url>
  <provider_name>Hatena Blog</provider_name>
  <provider_url>https://hatena.blog</provider_url>
  <published>2011-10-15 00:00:00</published>
  <title>Pythonで素数判定（3）</title>
  <type>rich</type>
  <url>https://inamori.hateblo.jp/entry/20111015/p1</url>
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