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  <author_name>jeneshicc</author_name>
  <author_url>https://blog.hatena.ne.jp/jeneshicc/</author_url>
  <blog_title>落書き、時々落学</blog_title>
  <blog_url>https://jeneshicc.hatenadiary.org/</blog_url>
  <categories>
    <anon>Project Euler</anon>
    <anon>Haskell</anon>
  </categories>
  <description>http://projecteuler.net/index.php?section=problems&amp;id=1081/a+1/b=1/nですが、b=n+b'と書き換えると n^2がb'で割り切れることが分かる。 従って、n^2が1999個の約数を持つ最小のnを探せばよい。 import Number import Data.List import Data.Maybe descending xs = and . zipWith (&gt;=) xs $ tail xs succ' (n+1) xs = let (ys,z:zs) = splitAt n xs in ys++[z+1]++zs nex…</description>
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  <provider_name>Hatena Blog</provider_name>
  <provider_url>https://hatena.blog</provider_url>
  <published>2008-11-26 17:27:21</published>
  <title>Problem 108</title>
  <type>rich</type>
  <url>https://jeneshicc.hatenadiary.org/entry/20081126/1227688041</url>
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