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  <author_name>jeneshicc</author_name>
  <author_url>https://blog.hatena.ne.jp/jeneshicc/</author_url>
  <blog_title>落書き、時々落学</blog_title>
  <blog_url>https://jeneshicc.hatenadiary.org/</blog_url>
  <categories>
    <anon>Project Euler</anon>
    <anon>Haskell</anon>
  </categories>
  <description>前門と同じような考え方。むしろこっちのほうが簡単だと思う。 choose n r = div (product [n-r+1..n]) $ product [1..r] replace m n = sum[choose (n+t-t*m) t | t&lt;-[1..div n m]] main = print.sum.zipWith replace [2,3,4] $ repeat 50</description>
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  <image_url></image_url>
  <provider_name>Hatena Blog</provider_name>
  <provider_url>https://hatena.blog</provider_url>
  <published>2008-11-28 21:10:21</published>
  <title>Problem 116</title>
  <type>rich</type>
  <url>https://jeneshicc.hatenadiary.org/entry/20081128/1227874221</url>
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