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  <author_name>jeneshicc</author_name>
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  <blog_title>落書き、時々落学</blog_title>
  <blog_url>https://jeneshicc.hatenadiary.org/</blog_url>
  <categories>
    <anon>日記</anon>
    <anon>Haskell</anon>
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  <description>LU分解@Haskell 遅延評価って便利．自分で評価の順番を明示的に与えなくても， よきにはからってくれる． import Data.Array type Matrix = Array (Int, Int) Double -- assumption: u!(i,i) /= 0 lu :: Matrix -&gt; (Matrix, Matrix) lu a = (l, u) where b = bounds a l = listArray b.map f.range $ b u = listArray b.map g.range $ b f (i,j) | i == j = 1 | i &lt; j =…</description>
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  <provider_name>Hatena Blog</provider_name>
  <provider_url>https://hatena.blog</provider_url>
  <published>2009-07-27 02:07:44</published>
  <title>LU分解</title>
  <type>rich</type>
  <url>https://jeneshicc.hatenadiary.org/entry/20090727/1248714464</url>
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