kagamiz https://blog.hatena.ne.jp/kagamiz/ Lilliput Steps https://kagamiz.hatenablog.com/ 微積分 数学 (1) $z=re^{i\theta}=r(\cos\theta+i\sin\theta)$としたとき, Cauchy-Riemann の微分方程式は, 実部を$u(r,\ \theta)$, 虚部を$v(r, \theta)$ とすると $\dfrac{\partial u}{\partial r} = \dfrac{1}{r}\dfrac{\partial v}{\partial \theta},\ \dfrac{\partial v}{\partial r} = -\dfrac{1}{r}\dfrac{\partial u}{\partial \theta}\ (r \neq 0)$とな… 190 <iframe src="https://hatenablog-parts.com/embed?url=https%3A%2F%2Fkagamiz.hatenablog.com%2Fentry%2F2013%2F12%2F24%2F132613" title="Cauchy-Riemann の微分方程式の極座標表示 - Lilliput Steps" class="embed-card embed-blogcard" scrolling="no" frameborder="0" style="display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;"></iframe> Hatena Blog https://hatena.blog 2013-12-24 13:26:13 rich https://kagamiz.hatenablog.com/entry/2013/12/24/132613 1.0 100%