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  <author_name>obelisk2</author_name>
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  <blog_title>Marginalia</blog_title>
  <blog_url>https://marginalia.hatenablog.com/</blog_url>
  <categories>
    <anon>AOJ</anon>
    <anon>Ruby</anon>
  </categories>
  <description>0200 Traveling Alone: One-way Ticket of Youth until (given = gets.split.map(&amp;:to_i)) == [0, 0] n, m = given edge = Array.new(m) {[]} h = Array.new(m) {[]} n.times do a, b, cost, time = gets.split.map(&amp;:to_i) a -= 1 b -= 1 edge[a][b] = edge[b][a] = [cost, time] h[a] &lt;&lt; b h[b] &lt;&lt; a end gets.to_i.times…</description>
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  <provider_name>Hatena Blog</provider_name>
  <provider_url>https://hatena.blog</provider_url>
  <published>2019-07-31 01:37:10</published>
  <title>AOJ（問題集）21</title>
  <type>rich</type>
  <url>https://marginalia.hatenablog.com/entry/2019/07/31/013710</url>
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