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  <author_name>mzp</author_name>
  <author_url>https://blog.hatena.ne.jp/mzp/</author_url>
  <blog_title>みずぴー日記</blog_title>
  <blog_url>https://mzp.hatenadiary.org/</blog_url>
  <categories>
    <anon>obsolute</anon>
    <anon>Python</anon>
    <anon>30分プログラム</anon>
  </categories>
  <description>30分プログラム、その334。Problem 57 - Project Euler。 2の平方根は無限に続く連分数で表すことができる. √ 2 = 1 + 1/(2 + 1/(2 + 1/(2 + ... ))) = 1.414213...最初の4回の繰り返しを展開すると以下が得られる. 1 + 1/2 = 3/2 = 1.5 1 + 1/(2 + 1/2) = 7/5 = 1.4 1 + 1/(2 + 1/(2 + 1/2)) = 17/12 = 1.41666... 1 + 1/(2 + 1/(2 + 1/(2 + 1/2))) = 41/29 = 1.41379... 次の3つの項は99…</description>
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  <image_url></image_url>
  <provider_name>Hatena Blog</provider_name>
  <provider_url>https://hatena.blog</provider_url>
  <published>2008-07-06 00:00:00</published>
  <title>Problem 57 - Project Euler</title>
  <type>rich</type>
  <url>https://mzp.hatenadiary.org/entry/20080706/euler</url>
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