partender810 https://blog.hatena.ne.jp/partender810/ Attack All Around https://partender810.hatenablog.com/ Challenge I use whatever exponent I want ファイル：chall.py from Crypto.Util.number import getPrime, inverse, bytes_to_long e = 1440 p = getPrime(1024) q = getPrime(1024) n = p * q flag = b"buckeye{???????????????????????????????}" c = pow(bytes_to_long(flag), e, n) print(f"e = {e}") print(f"p = {p}") pr… 190 <iframe src="https://hatenablog-parts.com/embed?url=https%3A%2F%2Fpartender810.hatenablog.com%2Fentry%2F2021%2F10%2F30%2F120348" title="Buckeye CTF Defective RSA writeup - Attack All Around" class="embed-card embed-blogcard" scrolling="no" frameborder="0" style="display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;"></iframe> https://cdn-ak.f.st-hatena.com/images/fotolife/p/partender810/20211027/20211027133536.png Hatena Blog https://hatena.blog 2021-10-30 12:03:48 rich https://partender810.hatenablog.com/entry/2021/10/30/120348 1.0 100%