rare_Remrin https://blog.hatena.ne.jp/rare_Remrin/ Remrinのpython攻略日記 https://python-remrin.hatenadiary.jp/ python ifの使い方について。 「1000未満の3または5の倍数の和を求める」場合 ○条件分岐 limit = 1000 result = 0 for i in range(limit): if i%3 == 0 or i%5 ==0: result += i print(result) ○内包表記 limit = 1000 result = sum([x for x in range(limit) if x%3 == 0 or x%5 ==0 ]) print(result) ○３項演算子 limit = 1000 result = 0 for i in range(limit): result +… 190 <iframe src="https://hatenablog-parts.com/embed?url=https%3A%2F%2Fpython-remrin.hatenadiary.jp%2Fentry%2F2017%2F05%2F22%2F163238" title="3つのif - Remrinのpython攻略日記" class="embed-card embed-blogcard" scrolling="no" frameborder="0" style="display: block; width: 100%; height: 190px; max-width: 500px; margin: 10px 0px;"></iframe> Hatena Blog https://hatena.blog 2017-05-22 16:32:38 rich https://python-remrin.hatenadiary.jp/entry/2017/05/22/163238 1.0 100%