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  <blog_title>how to code something</blog_title>
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  <description>ヤコビアンJのとき、 JJ^Tの固有ベクトルが長軸、短軸の方向を表し、 JJ^Tの固有値が長軸、短軸の大きさを表す。楕円の関係式 勉強しよう数学解答集: 原点の回りに回転した楕円の方程式から楕円の軸を計算する clear; close all; syms L1 L2 L3; syms th1 th2 th3; x1 = L1*cos(th1); y1 = L1*sin(th1); x2 = L1*cos(th1)+L2*cos(th1+th2); y2 = L1*sin(th1)+L2*sin(th1+th2); x3 = L1*cos(th1)+L2*cos(th1+th2)+L3*cos(…</description>
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  <published>2024-01-22 23:52:48</published>
  <title>可操作楕円体の計算</title>
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  <url>https://seinzumtode.hatenadiary.jp/entry/2024/01/22/235248</url>
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