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    <anon>プログラミング(JavaScript)</anon>
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  <description>trueになるから、条件式自体をreturnすればOK 変更前 'use strict'; { const numbers = [1, 4, 7, 8, 10]; const evenNumbers = numbers.filter(number =&gt;{ if(number % 2 === 0){ return true; }else{ return false; } }); console.log(evenNumbers); } // 実行結果 [ 4, 8, 10 ] 変更後 { const numbers = [1, 4, 7, 8, 10]; const evenNumbers = n…</description>
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  <provider_name>Hatena Blog</provider_name>
  <provider_url>https://hatena.blog</provider_url>
  <published>2020-04-08 07:00:00</published>
  <title>JavaScript 短く書いてみるメモ</title>
  <type>rich</type>
  <url>https://tako-eng.hatenablog.com/entry/2020/04/08/070000</url>
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