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  <author_name>tmurata</author_name>
  <author_url>https://blog.hatena.ne.jp/tmurata/</author_url>
  <blog_title>tmurataの日記</blog_title>
  <blog_url>https://tmurata.hatenadiary.org/</blog_url>
  <categories>
    <anon>SICP</anon>
  </categories>
  <description>集合の部分集合を作り出す手続きの次の定義 (define (subsets s) (if (null? s) (list ()) (let ((rest (subsets (cdr s)))) (append rest (map (lambda (x) (cons (car s) x)) rest))))) 実験 (subsets (list 1 2 3)) ; (() #0=(3) #1=(2) #2=(2 . #0#) (1) (1 . #0#) (1 . #1#) (1 . #2#)) うまくいかない…。何で? ということで、Google先生に聞いてみるとsubsetsの定義はこれでOK…</description>
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  <image_url></image_url>
  <provider_name>Hatena Blog</provider_name>
  <provider_url>https://hatena.blog</provider_url>
  <published>2009-05-20 08:58:33</published>
  <title>SICP問題2.32</title>
  <type>rich</type>
  <url>https://tmurata.hatenadiary.org/entry/20090520/1242777513</url>
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