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  <author_name>xef</author_name>
  <author_url>https://blog.hatena.ne.jp/xef/</author_url>
  <blog_title>Soleil cou coupe</blog_title>
  <blog_url>https://xef.hatenadiary.org/</blog_url>
  <categories>
    <anon>CoffeeScript</anon>
  </categories>
  <description>問題文 Problem 9 ピタゴラスの三つ組(ピタゴラスの定理を満たす自然数)とはa Solution 3重ループをひとつ減らす工夫をするのがコツ？ pythagorean ?= (a, b, c) -&gt; a*a + b*b == c*c for a in [1..1000] for b in [a..1000-a] c = 1000 - a - b if pythagorean? a, b, c console.log a*b*c 順路：CoffeeScriptでProject Euler #10 逆路：CoffeeScriptでProject Euler #8</description>
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  <provider_name>Hatena Blog</provider_name>
  <provider_url>https://hatena.blog</provider_url>
  <published>2012-03-31 00:00:02</published>
  <title>CoffeeScriptでProject Euler #9</title>
  <type>rich</type>
  <url>https://xef.hatenadiary.org/entry/20120331/p1</url>
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