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  <author_name>zehnpaard</author_name>
  <author_url>https://blog.hatena.ne.jp/zehnpaard/</author_url>
  <blog_title>Arantium Maestum</blog_title>
  <blog_url>https://zehnpaard.hatenablog.com/</blog_url>
  <categories>
    <anon>Clojure</anon>
    <anon>SICP</anon>
  </categories>
  <description>SICP1.3.1の問題1.33を解いてみる。 filtered-accumulateのiterative process版： (defn filtered-accumulate [combiner null-value filt f a next b] (loop [a a result null-value] (cond (&gt; a b) result (filt a) (recur (next a) (combiner (f a) result)) :else (recur (next a) result)))) （recursive process版は引数のあまりの多さ・複雑さがおぞまし…</description>
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  <provider_name>Hatena Blog</provider_name>
  <provider_url>https://hatena.blog</provider_url>
  <published>2016-06-03 14:54:02</published>
  <title>SICPの勉強 問題1.33</title>
  <type>rich</type>
  <url>https://zehnpaard.hatenablog.com/entry/2016/06/03/145402</url>
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